[#79440] [Ruby trunk Bug#13188] Reinitialize Ruby VM. — shyouhei@...
Issue #13188 has been updated by Shyouhei Urabe.
6 messages
2017/02/06
[#79441] Re: [Ruby trunk Bug#13188] Reinitialize Ruby VM.
— SASADA Koichi <ko1@...>
2017/02/06
On 2017/02/06 10:10, shyouhei@ruby-lang.org wrote:
[#79532] Immutable Strings vs Symbols — Daniel Ferreira <subtileos@...>
Hi,
15 messages
2017/02/15
[#79541] Re: Immutable Strings vs Symbols
— Rodrigo Rosenfeld Rosas <rr.rosas@...>
2017/02/15
Em 15-02-2017 05:05, Daniel Ferreira escreveu:
[#79543] Re: Immutable Strings vs Symbols
— Daniel Ferreira <subtileos@...>
2017/02/16
Hi Rodrigo,
[#79560] Re: Immutable Strings vs Symbols
— Rodrigo Rosenfeld Rosas <rr.rosas@...>
2017/02/16
Em 15-02-2017 22:39, Daniel Ferreira escreveu:
[ruby-core:79712] [Ruby trunk Feature#13219] bug in Math.sqrt(n).to_i, to compute integer squareroot, new word to accurately fix it
From:
tomoyapenguin@...
Date:
2017-02-23 04:34:05 UTC
List:
ruby-core #79712
Issue #13219 has been updated by tomoya ishida.
Newton seems to be faster than bbm, if the initial x is closer to √n.
when I use x=1<<((n.bit_length+1)/2) for the initial x in newton's method,
the iteration count (n=10**4000) became 11 (was 6656 when initial x is n).
I think the calculation cost is:
~~~
newton: O(log(k) * k**1.585))
Nathan Zook's isqrt: O(k**2)
bbm: O(k * k**1.585))
k=log(n)
bignum mult: O(k**1.585) # Bignum uses karatsuba algorithm
~~~
benchmark
~~~ruby
class Integer
def irootn(n)
return nil if self < 0 && n.even?
raise "root n is < 2 or not an Integer" unless n.is_a?(Integer) && n > 1
num = self.abs
bits_shift = (num.bit_length)/n + 2
root, bitn_mask = 0, (1 << bits_shift)
until (bitn_mask >>= 1) == 0
root |= bitn_mask
root ^= bitn_mask if root**n > num
end
root *= (self < 0 ? -1 : 1)
end
def iroot2; irootn(2) end
end
def intsqrt7(n) # Newton's method
x = n
y = (n + 1)/2
while y < x
x = y
y = (x + n/x)/2
end
x
end
def intsqrt7_with_good_initial_value(n) # Newton's method with √n < initial_x <= 2*√n
raise if n<0
return n if n<=1
x = 1<<((n.bit_length+1)/2)
y = (x + n/x)/2
while y < x
x = y
y = (x + n/x)/2
end
x
end
require "benchmark/ips"
raise unless 100000.times.all?{|i|intsqrt7_with_good_initial_value(i) == i.iroot2}
Benchmark.ips do |x|
exp = 4000; n = 10**exp
puts "integer squareroot tests for n = 10**#{exp}"
x.report("iroot2" ) { n.iroot2 }
x.report("newtons" ) { intsqrt7(n) }
x.report("newtons_fast" ) { intsqrt7_with_good_initial_value(n) }
x.compare!
end
~~~
result
~~~
integer squareroot tests for n = 10**4000
Warming up --------------------------------------
iroot2 1.000 i/100ms
newtons 1.000 i/100ms
newtons_fast 90.000 i/100ms
Calculating -------------------------------------
iroot2 13.054 (±15.3%) i/s - 64.000 in 5.063850s
newtons 2.455 (± 0.0%) i/s - 13.000 in 5.337181s
newtons_fast 939.494 (± 7.3%) i/s - 4.680k in 5.022312s
Comparison:
newtons_fast: 939.5 i/s
iroot2: 13.1 i/s - 71.97x slower
newtons: 2.5 i/s - 382.74x slower
~~~
----------------------------------------
Feature #13219: bug in Math.sqrt(n).to_i, to compute integer squareroot, new word to accurately fix it
https://bugs.ruby-lang.org/issues/13219#change-63134
* Author: Jabari Zakiya
* Status: Open
* Priority: Normal
* Assignee:
* Target version:
----------------------------------------
In doing a math application using **Math.sqrt(n).to_i** to compute integer squareroots
of integers I started noticing errors for numbers > 10**28.
I coded an algorithm that accurately computes the integer squareroot for arbirary sized numbers
but its significantly slower than the math library written in C.
Thus, I request a new method **Math.intsqrt(n)** be created, that is coded in C and part of the
core library, that will compute the integer squareroots of integers accurately and fast.
Here is working highlevel code to accurately compute the integer squareroot.
```
def intsqrt(n)
bits_shift = (n.to_s(2).size)/2 + 1
bitn_mask = root = 1 << bits_shift
while true
root ^= bitn_mask if (root * root) > n
bitn_mask >>= 1
return root if bitn_mask == 0
root |= bitn_mask
end
end
def intsqrt1(n)
return n if n | 1 == 1 # if n is 0 or 1
bits_shift = (Math.log2(n).ceil)/2 + 1
bitn_mask = root = 1 << bits_shift
while true
root ^= bitn_mask if (root * root) > n
bitn_mask >>= 1
return root if bitn_mask == 0
root |= bitn_mask
end
end
require "benchmark/ips"
Benchmark.ips do |x|
n = 10**40
puts "integer squareroot tests for n = #{n}"
x.report("intsqrt(n)" ) { intsqrt(n) }
x.report("intsqrt1(n)" ) { intsqrt1(n) }
x.report("Math.sqrt(n).to_i") { Math.sqrt(n).to_i }
x.compare!
end
```
Here's why it needs to be done in C.
```
2.4.0 :178 > load 'intsqrttest.rb'
integer squareroot tests for n = 10000000000000000000000000000000000000000
Warming up --------------------------------------
intsqrt(n) 5.318k i/100ms
intsqrt1(n) 5.445k i/100ms
Math.sqrt(n).to_i 268.281k i/100ms
Calculating -------------------------------------
intsqrt(n) 54.219k (± 5.5%) i/s - 271.218k in 5.017552s
intsqrt1(n) 55.872k (± 5.4%) i/s - 283.140k in 5.082953s
Math.sqrt(n).to_i 5.278M (± 6.1%) i/s - 26.560M in 5.050707s
Comparison:
Math.sqrt(n).to_i: 5278477.8 i/s
intsqrt1(n): 55871.7 i/s - 94.47x slower
intsqrt(n): 54219.4 i/s - 97.35x slower
=> true
2.4.0 :179 >
```
Here are examples of math errors using **Math.sqrt(n).to_i** run on Ruby-2.4.0.
```
2.4.0 :101 > n = 10**27; puts n, (a = intsqrt(n)), a*a, (b = intsqrt1(n)), b*b, (c = Math.sqrt(n).to_i), c*c
1000000000000000000000000000
31622776601683
999999999999949826038432489
31622776601683
999999999999949826038432489
31622776601683
999999999999949826038432489
=> nil
2.4.0 :102 > n = 10**28; puts n, (a = intsqrt(n)), a*a, (b = intsqrt1(n)), b*b, (c = Math.sqrt(n).to_i), c*c
10000000000000000000000000000
100000000000000
10000000000000000000000000000
100000000000000
10000000000000000000000000000
100000000000000
10000000000000000000000000000
=> nil
2.4.0 :103 > n = 10**29; puts n, (a = intsqrt(n)), a*a, (b = intsqrt1(n)), b*b, (c = Math.sqrt(n).to_i), c*c
100000000000000000000000000000
316227766016837
99999999999999409792567484569
316227766016837
99999999999999409792567484569
316227766016837
99999999999999409792567484569
=> nil
2.4.0 :104 > n = 10**30; puts n, (a = intsqrt(n)), a*a, (b = intsqrt1(n)), b*b, (c = Math.sqrt(n).to_i), c*c
1000000000000000000000000000000
1000000000000000
1000000000000000000000000000000
1000000000000000
1000000000000000000000000000000
1000000000000000
1000000000000000000000000000000
=> nil
2.4.0 :105 > n = 10**31; puts n, (a = intsqrt(n)), a*a, (b = intsqrt1(n)), b*b, (c = Math.sqrt(n).to_i), c*c
10000000000000000000000000000000
3162277660168379
9999999999999997900254631487641
3162277660168379
9999999999999997900254631487641
3162277660168379
9999999999999997900254631487641
=> nil
2.4.0 :106 > n = 10**32; puts n, (a = intsqrt(n)), a*a, (b = intsqrt1(n)), b*b, (c = Math.sqrt(n).to_i), c*c
100000000000000000000000000000000
10000000000000000
100000000000000000000000000000000
10000000000000000
100000000000000000000000000000000
10000000000000000
100000000000000000000000000000000
=> nil
2.4.0 :107 > n = 10**33; puts n, (a = intsqrt(n)), a*a, (b = intsqrt1(n)), b*b, (c = Math.sqrt(n).to_i), c*c
1000000000000000000000000000000000
31622776601683793
999999999999999979762122758866849
31622776601683793
999999999999999979762122758866849
31622776601683792
999999999999999916516569555499264
=> nil
2.4.0 :108 > n = 10**34; puts n, (a = intsqrt(n)), a*a, (b = intsqrt1(n)), b*b, (c = Math.sqrt(n).to_i), c*c
10000000000000000000000000000000000
100000000000000000
10000000000000000000000000000000000
100000000000000000
10000000000000000000000000000000000
100000000000000000
10000000000000000000000000000000000
=> nil
2.4.0 :109 > n = 10**35; puts n, (a = intsqrt(n)), a*a, (b = intsqrt1(n)), b*b, (c = Math.sqrt(n).to_i), c*c
100000000000000000000000000000000000
316227766016837933
99999999999999999873578871987712489
316227766016837933
99999999999999999873578871987712489
316227766016837952
100000000000000011890233980627554304
=> nil
2.4.0 :110 > n = 10**36; puts n, (a = intsqrt(n)), a*a, (b = intsqrt1(n)), b*b, (c = Math.sqrt(n).to_i), c*c
1000000000000000000000000000000000000
1000000000000000000
1000000000000000000000000000000000000
1000000000000000000
1000000000000000000000000000000000000
1000000000000000000
1000000000000000000000000000000000000
=> nil
2.4.0 :111 > n = 10**37; puts n, (a = intsqrt(n)), a*a, (b = intsqrt1(n)), b*b, (c = Math.sqrt(n).to_i), c*c
10000000000000000000000000000000000000
3162277660168379331
9999999999999999993682442519108007561
3162277660168379331
9999999999999999993682442519108007561
3162277660168379392
10000000000000000379480317059650289664
=> nil
2.4.0 :112 >
```
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